We have a hydrogen there and we have a carbon try chloride substitution year, which should be coming out at the appropriate pinkel. And on this carbon we have, um, Ethel going into the page.
We have a C H which is coming out of the page from this carbon. So let's go ahead and write the two molecules. So the third situation third molecule which were given is a little more difficult to think about because we have two carbons in a chain here. So if we think about rotating them, trying to get them to be superimposed, we can see that that's not possible. And the mean group would be going in so that we say they are an anti murders because they are non super imposible mirror images waken see right from here that they are mere emerges. We would see that the method group here would be rotated, so that's coming out. And if we can think three dimensionally or as well as we can in two dimensions, we cannot find a way in which we could superimpose thes if we were to rotate this molecule here so that the hydrogen and bro Ming are in the same position is on the left the left. So we notice about this structure is that we do have four different substitute wants. If we write the second structure can right, bro mean metal going into the page. You have a high fashion, bro Mean, I have a method group going into the page and then in a mean group coming out. So let's go ahead and write the structures down here. So the second set of molecules which were given is once again we have a tetra Usual carbon. We could superimpose these two molecules on each other. So an anti Mars exhibit optical asama, is, um And so since we have to substitution sees two metal groups. The question here Do we have, um, and Auntie Mers, or do we have the same molecules? Now? What we notice here is that we have to substitute wants, which are the same. Once again, we have the hydra axel coming out of the page in another method going into the page.
And then another method going into the page in the second part gives us, uh, something that looks like this we have here. I had out alcohol hydroxyl group coming out of the page. So the first one were given a methyl group CEO. So let's go ahead and serve with a and let's reproduce the structures given here.
This question gives us three different pairs of molecules and we need to determine whether they're the same identical or an anthem. No, we'Ll work on problem forty from chapter twenty one.
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